$ aws lambda invoke --function-name my-function out.json --log-type Tail \ --query 'LogResult' --output text | base64 -d START RequestId: fc4f8810-88ff-4800-974c ...

Kafka connector with PyFlink. Hello, I am trying to deploy a Python job with Kafka connector: from pyflink.datastream import StreamExecutionEnvironment from pyflink.dataset import...

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522022 paste into package explorer should understand module-info. java [verified/fixed] 526833 revisit default set of JDK modules in ModuleDialog (modular project) [resolved/fixed] 527023 Moving from non-modular buildpath to modular puts JRE 9 on classpath and doesn't update the internal structure [verified/fixed]

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    2 days ago · A module can find out its own module name by looking at the predefined global variable __name__. If this has the value '__main__' , the program is running as a script. Many modules that are usually used by importing them also provide a command-line interface or a self-test, and only execute this code after checking __name__ :

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    <pre> Lambda can't find the file decode-verify-jwt.js. Make sure that your handler upholds the format: file-name.method. </pre> Solution. I uploaded the file by using a zip. I zipped the parent directory, so my starting module was not in the root directory, but one level under that. So there are two ways to fix it:

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